4v-1+4(2v+4)=-3(v+1)

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Solution for 4v-1+4(2v+4)=-3(v+1) equation: 



4v-1+4(2v+4)=-3(v+1)

We move all terms to the left:

4v-1+4(2v+4)-(-3(v+1))=0

We multiply parentheses

4v+8v-(-3(v+1))+16-1=0



We calculate terms in parentheses: -(-3(v+1)), so:

-3(v+1)

We multiply parentheses

-3v-3

Back to the equation:

-(-3v-3)



We add all the numbers together, and all the variables

12v-(-3v-3)+15=0

We get rid of parentheses

12v+3v+3+15=0

We add all the numbers together, and all the variables

15v+18=0

We move all terms containing v to the left, all other terms to the right

15v=-18

v=-18/15

v=-1+1/5

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