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5(x-5)-4=-1+(x+4)
We move all terms to the left:
5(x-5)-4-(-1+(x+4))=0
We multiply parentheses
5x-(-1+(x+4))-25-4=0
We calculate terms in parentheses: -(-1+(x+4)), so:We add all the numbers together, and all the variables
-1+(x+4)
determiningTheFunctionDomain (x+4)-1
We get rid of parentheses
x+4-1
We add all the numbers together, and all the variables
x+3
Back to the equation:
-(x+3)
5x-(x+3)-29=0
We get rid of parentheses
5x-x-3-29=0
We add all the numbers together, and all the variables
4x-32=0
We move all terms containing x to the left, all other terms to the right
4x=32
x=32/4
x=8
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