4x-(3x-4)=6x-(3-8x)+(-2x+29)

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Solution for 4x-(3x-4)=6x-(3-8x)+(-2x+29) equation: 



4x-(3x-4)=6x-(3-8x)+(-2x+29)

We move all terms to the left:

4x-(3x-4)-(6x-(3-8x)+(-2x+29))=0

We add all the numbers together, and all the variables

4x-(3x-4)-(6x-(-8x+3)+(-2x+29))=0

We get rid of parentheses

4x-3x-(6x-(-8x+3)+(-2x+29))+4=0



We calculate terms in parentheses: -(6x-(-8x+3)+(-2x+29)), so:

6x-(-8x+3)+(-2x+29)

We get rid of parentheses

6x+8x-2x-3+29

We add all the numbers together, and all the variables

12x+26

Back to the equation:

-(12x+26)



We add all the numbers together, and all the variables

x-(12x+26)+4=0

We get rid of parentheses

x-12x-26+4=0

We add all the numbers together, and all the variables

-11x-22=0

We move all terms containing x to the left, all other terms to the right

-11x=22

x=22/-11

x=-2

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