6(x+3)+2(x-5)=4(x-3)+3(x+7)

Solution for 6(x+3)+2(x-5)=4(x-3)+3(x+7) equation:

6(x+3)+2(x-5)=4(x-3)+3(x+7)

We move all terms to the left:

6(x+3)+2(x-5)-(4(x-3)+3(x+7))=0

We multiply parentheses

6x+2x-(4(x-3)+3(x+7))+18-10=0


We calculate terms in parentheses: -(4(x-3)+3(x+7)), so:

4(x-3)+3(x+7)

We multiply parentheses

4x+3x-12+21

We add all the numbers together, and all the variables

7x+9

Back to the equation:

-(7x+9)


We add all the numbers together, and all the variables

8x-(7x+9)+8=0

We get rid of parentheses

8x-7x-9+8=0

We add all the numbers together, and all the variables

x-1=0

We move all terms containing x to the left, all other terms to the right

x=1