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5(x-2)-x=2(x+5)-4
We move all terms to the left:
5(x-2)-x-(2(x+5)-4)=0
We add all the numbers together, and all the variables
-1x+5(x-2)-(2(x+5)-4)=0
We multiply parentheses
-1x+5x-(2(x+5)-4)-10=0
We calculate terms in parentheses: -(2(x+5)-4), so:We add all the numbers together, and all the variables
2(x+5)-4
We multiply parentheses
2x+10-4
We add all the numbers together, and all the variables
2x+6
Back to the equation:
-(2x+6)
4x-(2x+6)-10=0
We get rid of parentheses
4x-2x-6-10=0
We add all the numbers together, and all the variables
2x-16=0
We move all terms containing x to the left, all other terms to the right
2x=16
x=16/2
x=8
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