6(3x)=2(9x-5)+10

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Solution for 6(3x)=2(9x-5)+10 equation: 



6(3x)=2(9x-5)+10

We move all terms to the left:

6(3x)-(2(9x-5)+10)=0



We calculate terms in parentheses: -(2(9x-5)+10), so:

2(9x-5)+10

We multiply parentheses

18x-10+10

We add all the numbers together, and all the variables

18x

Back to the equation:

-(18x)



We add all the numbers together, and all the variables

45x=0

x=0/45

x=0

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