7x-3x+7x=3(x-4)+20

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Solution for 7x-3x+7x=3(x-4)+20 equation: 



7x-3x+7x=3(x-4)+20

We move all terms to the left:

7x-3x+7x-(3(x-4)+20)=0

We add all the numbers together, and all the variables

11x-(3(x-4)+20)=0



We calculate terms in parentheses: -(3(x-4)+20), so:

3(x-4)+20

We multiply parentheses

3x-12+20

We add all the numbers together, and all the variables

3x+8

Back to the equation:

-(3x+8)



We get rid of parentheses

11x-3x-8=0

We add all the numbers together, and all the variables

8x-8=0

We move all terms containing x to the left, all other terms to the right

8x=8

x=8/8

x=1

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