5(x-2)+3x=2-2(x-4)

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Solution for 5(x-2)+3x=2-2(x-4) equation: 



5(x-2)+3x=2-2(x-4)

We move all terms to the left:

5(x-2)+3x-(2-2(x-4))=0

We add all the numbers together, and all the variables

3x+5(x-2)-(2-2(x-4))=0

We multiply parentheses

3x+5x-(2-2(x-4))-10=0



We calculate terms in parentheses: -(2-2(x-4)), so:

2-2(x-4)

determiningTheFunctionDomain
-2(x-4)+2

We multiply parentheses

-2x+8+2

We add all the numbers together, and all the variables

-2x+10

Back to the equation:

-(-2x+10)



We add all the numbers together, and all the variables

8x-(-2x+10)-10=0

We get rid of parentheses

8x+2x-10-10=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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