(1/10)x+x+x-135=180

Solution for (1/10)x+x+x-135=180 equation:

(1/10)x+x+x-135=180

We move all terms to the left:

(1/10)x+x+x-135-(180)=0


Domain of the equation: 10)x!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

(+1/10)x+x+x-135-180=0

We add all the numbers together, and all the variables

2x+(+1/10)x-315=0

We multiply parentheses

x^2+2x-315=0

a = 1; b = 2; c = -315;
Δ = b2-4ac
Δ = 22-4·1·(-315)
Δ = 1264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1264}=\sqrt{16*79}=\sqrt{16}*\sqrt{79}=4\sqrt{79}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-4\sqrt{79}}{2*1}=\frac{-2-4\sqrt{79}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+4\sqrt{79}}{2*1}=\frac{-2+4\sqrt{79}}{2}
$