2(x-4)+6=x+(x-5)+3

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Solution for 2(x-4)+6=x+(x-5)+3 equation: 



2(x-4)+6=x+(x-5)+3

We move all terms to the left:

2(x-4)+6-(x+(x-5)+3)=0

We multiply parentheses

2x-(x+(x-5)+3)-8+6=0



We calculate terms in parentheses: -(x+(x-5)+3), so:

x+(x-5)+3

We get rid of parentheses

x+x-5+3

We add all the numbers together, and all the variables

2x-2

Back to the equation:

-(2x-2)



We add all the numbers together, and all the variables

2x-(2x-2)-2=0

We get rid of parentheses

2x-2x+2-2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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