5(x-2)+2x=2(x+5)x

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Solution for 5(x-2)+2x=2(x+5)x equation:



5(x-2)+2x=2(x+5)x
We move all terms to the left:
5(x-2)+2x-(2(x+5)x)=0
We add all the numbers together, and all the variables
2x+5(x-2)-(2(x+5)x)=0
We multiply parentheses
2x+5x-(2(x+5)x)-10=0
We calculate terms in parentheses: -(2(x+5)x), so:
2(x+5)x
We multiply parentheses
2x^2+10x
Back to the equation:
-(2x^2+10x)
We add all the numbers together, and all the variables
7x-(2x^2+10x)-10=0
We get rid of parentheses
-2x^2+7x-10x-10=0
We add all the numbers together, and all the variables
-2x^2-3x-10=0
a = -2; b = -3; c = -10;
Δ = b2-4ac
Δ = -32-4·(-2)·(-10)
Δ = -71
Delta is less than zero, so there is no solution for the equation

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