1/4b2=16

Solution for 1/4b2=16 equation:

1/4b^2=16

We move all terms to the left:

1/4b^2-(16)=0


Domain of the equation: 4b^2!=0

b^2!=0/4

b^2!=√0

b!=0

b∈R


We multiply all the terms by the denominator


-16*4b^2+1=0

Wy multiply elements

-64b^2+1=0

a = -64; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-64)·1
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16}{2*-64}=\frac{-16}{-128}
=1/8
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16}{2*-64}=\frac{16}{-128}
=-1/8
$