5(x+7)+2=4(x-4)+1

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Solution for 5(x+7)+2=4(x-4)+1 equation: 



5(x+7)+2=4(x-4)+1

We move all terms to the left:

5(x+7)+2-(4(x-4)+1)=0

We multiply parentheses

5x-(4(x-4)+1)+35+2=0



We calculate terms in parentheses: -(4(x-4)+1), so:

4(x-4)+1

We multiply parentheses

4x-16+1

We add all the numbers together, and all the variables

4x-15

Back to the equation:

-(4x-15)



We add all the numbers together, and all the variables

5x-(4x-15)+37=0

We get rid of parentheses

5x-4x+15+37=0

We add all the numbers together, and all the variables

x+52=0

We move all terms containing x to the left, all other terms to the right

x=-52

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