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2/3x-5/8x=25
We move all terms to the left:
2/3x-5/8x-(25)=0
Domain of the equation: 3x!=0
x!=0/3
x!=0
x∈R
Domain of the equation: 8x!=0We calculate fractions
x!=0/8
x!=0
x∈R
16x/24x^2+(-15x)/24x^2-25=0
We multiply all the terms by the denominator
16x+(-15x)-25*24x^2=0
Wy multiply elements
-600x^2+16x+(-15x)=0
We get rid of parentheses
-600x^2+16x-15x=0
We add all the numbers together, and all the variables
-600x^2+x=0
a = -600; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-600)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1}=1$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-600}=\frac{-2}{-1200} =1/600 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-600}=\frac{0}{-1200} =0 $
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