5(x+2)=13+4x(2x-1)

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Solution for 5(x+2)=13+4x(2x-1) equation: 



5(x+2)=13+4x(2x-1)

We move all terms to the left:

5(x+2)-(13+4x(2x-1))=0

We multiply parentheses

5x-(13+4x(2x-1))+10=0



We calculate terms in parentheses: -(13+4x(2x-1)), so:

13+4x(2x-1)

determiningTheFunctionDomain
4x(2x-1)+13

We multiply parentheses

8x^2-4x+13

Back to the equation:

-(8x^2-4x+13)



We get rid of parentheses

-8x^2+5x+4x-13+10=0

We add all the numbers together, and all the variables

-8x^2+9x-3=0

a = -8; b = 9; c = -3;
Δ = b2-4ac
Δ = 92-4·(-8)·(-3)
Δ = -15
Delta is less than zero, so there is no solution for the equation

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