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(2x+3)(x)=350
We move all terms to the left:
(2x+3)(x)-(350)=0
We multiply parentheses
2x^2+3x-350=0
a = 2; b = 3; c = -350;
Δ = b2-4ac
Δ = 32-4·2·(-350)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-53}{2*2}=\frac{-56}{4} =-14 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+53}{2*2}=\frac{50}{4} =12+1/2 $
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