6t2=32

Solution for 6t2=32 equation:

6t^2=32

We move all terms to the left:

6t^2-(32)=0

a = 6; b = 0; c = -32;
Δ = b2-4ac
Δ = 02-4·6·(-32)
Δ = 768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{768}=\sqrt{256*3}=\sqrt{256}*\sqrt{3}=16\sqrt{3}$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{3}}{2*6}=\frac{0-16\sqrt{3}}{12}
=-\frac{16\sqrt{3}}{12}
=-\frac{4\sqrt{3}}{3}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{3}}{2*6}=\frac{0+16\sqrt{3}}{12}
=\frac{16\sqrt{3}}{12}
=\frac{4\sqrt{3}}{3}
$