5(v+4)=-2(4v-5)+7v

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Solution for 5(v+4)=-2(4v-5)+7v equation:



5(v+4)=-2(4v-5)+7v
We move all terms to the left:
5(v+4)-(-2(4v-5)+7v)=0
We multiply parentheses
5v-(-2(4v-5)+7v)+20=0
We calculate terms in parentheses: -(-2(4v-5)+7v), so:
-2(4v-5)+7v
We add all the numbers together, and all the variables
7v-2(4v-5)
We multiply parentheses
7v-8v+10
We add all the numbers together, and all the variables
-1v+10
Back to the equation:
-(-1v+10)
We get rid of parentheses
5v+1v-10+20=0
We add all the numbers together, and all the variables
6v+10=0
We move all terms containing v to the left, all other terms to the right
6v=-10
v=-10/6
v=-1+2/3

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