-2(6y-3)+4y=4(y+4)

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Solution for -2(6y-3)+4y=4(y+4) equation: 



-2(6y-3)+4y=4(y+4)

We move all terms to the left:

-2(6y-3)+4y-(4(y+4))=0

We add all the numbers together, and all the variables

4y-2(6y-3)-(4(y+4))=0

We multiply parentheses

4y-12y-(4(y+4))+6=0



We calculate terms in parentheses: -(4(y+4)), so:

4(y+4)

We multiply parentheses

4y+16

Back to the equation:

-(4y+16)



We add all the numbers together, and all the variables

-8y-(4y+16)+6=0

We get rid of parentheses

-8y-4y-16+6=0

We add all the numbers together, and all the variables

-12y-10=0

We move all terms containing y to the left, all other terms to the right

-12y=10

y=10/-12

y=-5/6

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