2(2y+3)+2(y-3)=-18

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Solution for 2(2y+3)+2(y-3)=-18 equation: 



2(2y+3)+2(y-3)=-18

We move all terms to the left:

2(2y+3)+2(y-3)-(-18)=0

We add all the numbers together, and all the variables

2(2y+3)+2(y-3)+18=0

We multiply parentheses

4y+2y+6-6+18=0

We add all the numbers together, and all the variables

6y+18=0

We move all terms containing y to the left, all other terms to the right

6y=-18

y=-18/6

y=-3

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