5(t-3)=4(t+2)

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Solution for 5(t-3)=4(t+2) equation: 



5(t-3)=4(t+2)

We move all terms to the left:

5(t-3)-(4(t+2))=0

We multiply parentheses

5t-(4(t+2))-15=0



We calculate terms in parentheses: -(4(t+2)), so:

4(t+2)

We multiply parentheses

4t+8

Back to the equation:

-(4t+8)



We get rid of parentheses

5t-4t-8-15=0

We add all the numbers together, and all the variables

t-23=0

We move all terms containing t to the left, all other terms to the right

t=23

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