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X+5(X-1)=4-3(3X-5)
We move all terms to the left:
X+5(X-1)-(4-3(3X-5))=0
We multiply parentheses
X+5X-(4-3(3X-5))-5=0
We calculate terms in parentheses: -(4-3(3X-5)), so:We add all the numbers together, and all the variables
4-3(3X-5)
determiningTheFunctionDomain -3(3X-5)+4
We multiply parentheses
-9X+15+4
We add all the numbers together, and all the variables
-9X+19
Back to the equation:
-(-9X+19)
6X-(-9X+19)-5=0
We get rid of parentheses
6X+9X-19-5=0
We add all the numbers together, and all the variables
15X-24=0
We move all terms containing X to the left, all other terms to the right
15X=24
X=24/15
X=1+3/5
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