(8x-20)+(3x-5)=100

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Solution for (8x-20)+(3x-5)=100 equation: 



(8x-20)+(3x-5)=100

We move all terms to the left:

(8x-20)+(3x-5)-(100)=0

We get rid of parentheses

8x+3x-20-5-100=0

We add all the numbers together, and all the variables

11x-125=0

We move all terms containing x to the left, all other terms to the right

11x=125

x=125/11

x=11+4/11

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