5(r-5)=4(r+1)

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Solution for 5(r-5)=4(r+1) equation: 



5(r-5)=4(r+1)

We move all terms to the left:

5(r-5)-(4(r+1))=0

We multiply parentheses

5r-(4(r+1))-25=0



We calculate terms in parentheses: -(4(r+1)), so:

4(r+1)

We multiply parentheses

4r+4

Back to the equation:

-(4r+4)



We get rid of parentheses

5r-4r-4-25=0

We add all the numbers together, and all the variables

r-29=0

We move all terms containing r to the left, all other terms to the right

r=29

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