11/m+3=5/2m=1/m-5

Solution for 11/m+3=5/2m=1/m-5 equation:

11/m+3=5/2m=1/m-5

We move all terms to the left:

11/m+3-(5/2m)=0


Domain of the equation: m!=0

m∈R



Domain of the equation: 2m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

11/m-(+5/2m)+3=0

We get rid of parentheses

11/m-5/2m+3=0

We calculate fractions


22m/2m^2+(-5m)/2m^2+3=0

We multiply all the terms by the denominator


22m+(-5m)+3*2m^2=0

Wy multiply elements

6m^2+22m+(-5m)=0

We get rid of parentheses

6m^2+22m-5m=0

We add all the numbers together, and all the variables

6m^2+17m=0

a = 6; b = 17; c = 0;
Δ = b2-4ac
Δ = 172-4·6·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(17)-17}{2*6}=\frac{-34}{12}
=-2+5/6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(17)+17}{2*6}=\frac{0}{12}
=0
$