(8x-8)(4x-2)=0

Solution for (8x-8)(4x-2)=0 equation:

(8x-8)(4x-2)=0

We multiply parentheses ..

(+32x^2-16x-32x+16)=0

We get rid of parentheses

32x^2-16x-32x+16=0

We add all the numbers together, and all the variables

32x^2-48x+16=0

a = 32; b = -48; c = +16;
Δ = b2-4ac
Δ = -482-4·32·16
Δ = 256
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{256}=16$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-48)-16}{2*32}=\frac{32}{64}
=1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-48)+16}{2*32}=\frac{64}{64}
=1
$