5(r-45)/2=2(3-2r)/5

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Solution for 5(r-45)/2=2(3-2r)/5 equation: 



5(r-45)/2=2(3-2r)/5

We move all terms to the left:

5(r-45)/2-(2(3-2r)/5)=0

We add all the numbers together, and all the variables

5(r-45)/2-(2(-2r+3)/5)=0

We calculate fractions


5r/()+(-(2(-2r+3)*2)/()=0



We calculate terms in parentheses: +(-(2(-2r+3)*2)/(), so:

-(2(-2r+3)*2)/(

We multiply all the terms by the denominator


-(2(-2r+3)*2)



We calculate terms in parentheses: -(2(-2r+3)*2), so:

2(-2r+3)*2

We multiply parentheses

-8r+12

Back to the equation:

-(-8r+12)



We get rid of parentheses

8r-12

Back to the equation:

+(8r-12)



We get rid of parentheses

5r/()+8r-12=0

We multiply all the terms by the denominator


5r+8r*()-12*()=0

We add all the numbers together, and all the variables

5r+8r*()=0

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