(r-45)/2=(3-2r)/5

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Solution for (r-45)/2=(3-2r)/5 equation: 



(r-45)/2=(3-2r)/5

We move all terms to the left:

(r-45)/2-((3-2r)/5)=0

We add all the numbers together, and all the variables

(r-45)/2-((-2r+3)/5)=0

We calculate fractions


r/()+(-((-2r+3)*2)/()=0



We calculate terms in parentheses: +(-((-2r+3)*2)/(), so:

-((-2r+3)*2)/(

We multiply all the terms by the denominator


-((-2r+3)*2)



We calculate terms in parentheses: -((-2r+3)*2), so:

(-2r+3)*2

We multiply parentheses

-4r+6

Back to the equation:

-(-4r+6)



We get rid of parentheses

4r-6

Back to the equation:

+(4r-6)



We get rid of parentheses

r/()+4r-6=0

We multiply all the terms by the denominator


r+4r*()-6*()=0

We add all the numbers together, and all the variables

r+4r*()=0

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