6(5y-2)+5(2y+6)=25(3y+2)-15y

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Solution for 6(5y-2)+5(2y+6)=25(3y+2)-15y equation: 



6(5y-2)+5(2y+6)=25(3y+2)-15y

We move all terms to the left:

6(5y-2)+5(2y+6)-(25(3y+2)-15y)=0

We multiply parentheses

30y+10y-(25(3y+2)-15y)-12+30=0



We calculate terms in parentheses: -(25(3y+2)-15y), so:

25(3y+2)-15y

We add all the numbers together, and all the variables

-15y+25(3y+2)

We multiply parentheses

-15y+75y+50

We add all the numbers together, and all the variables

60y+50

Back to the equation:

-(60y+50)



We add all the numbers together, and all the variables

40y-(60y+50)+18=0

We get rid of parentheses

40y-60y-50+18=0

We add all the numbers together, and all the variables

-20y-32=0

We move all terms containing y to the left, all other terms to the right

-20y=32

y=32/-20

y=-1+3/5

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