6(x-5)-2(4x+2)=100

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Solution for 6(x-5)-2(4x+2)=100 equation: 



6(x-5)-2(4x+2)=100

We move all terms to the left:

6(x-5)-2(4x+2)-(100)=0

We multiply parentheses

6x-8x-30-4-100=0

We add all the numbers together, and all the variables

-2x-134=0

We move all terms containing x to the left, all other terms to the right

-2x=134

x=134/-2

x=-67

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