5(n+2)=40+3n

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Solution for 5(n+2)=40+3n equation: 



5(n+2)=40+3n

We move all terms to the left:

5(n+2)-(40+3n)=0

We add all the numbers together, and all the variables

5(n+2)-(3n+40)=0

We multiply parentheses

5n-(3n+40)+10=0

We get rid of parentheses

5n-3n-40+10=0

We add all the numbers together, and all the variables

2n-30=0

We move all terms containing n to the left, all other terms to the right

2n=30

n=30/2

n=15

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