2(g-3)+1=-7g-4

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Solution for 2(g-3)+1=-7g-4 equation: 



2(g-3)+1=-7g-4

We move all terms to the left:

2(g-3)+1-(-7g-4)=0

We multiply parentheses

2g-(-7g-4)-6+1=0

We get rid of parentheses

2g+7g+4-6+1=0

We add all the numbers together, and all the variables

9g-1=0

We move all terms containing g to the left, all other terms to the right

9g=1

g=1/9

g=1/9

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