2y+5/2=35

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Solution for 2y+5/2=35 equation: 



2y+5/2=35

We move all terms to the left:

2y+5/2-(35)=0

determiningTheFunctionDomain
2y-35+5/2=0

We multiply all the terms by the denominator


2y*2+5-35*2=0

We add all the numbers together, and all the variables

2y*2-65=0

Wy multiply elements

4y-65=0

We move all terms containing y to the left, all other terms to the right

4y=65

y=65/4

y=16+1/4

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