2(4y+-5)=-42

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Solution for 2(4y+-5)=-42 equation: 



2(4y+-5)=-42

We move all terms to the left:

2(4y+-5)-(-42)=0

We add all the numbers together, and all the variables

2(4y-5)-(-42)=0

We add all the numbers together, and all the variables

2(4y-5)+42=0

We multiply parentheses

8y-10+42=0

We add all the numbers together, and all the variables

8y+32=0

We move all terms containing y to the left, all other terms to the right

8y=-32

y=-32/8

y=-4

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