5(m+1)=7(2+2m)

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Solution for 5(m+1)=7(2+2m) equation: 



5(m+1)=7(2+2m)

We move all terms to the left:

5(m+1)-(7(2+2m))=0

We add all the numbers together, and all the variables

5(m+1)-(7(2m+2))=0

We multiply parentheses

5m-(7(2m+2))+5=0



We calculate terms in parentheses: -(7(2m+2)), so:

7(2m+2)

We multiply parentheses

14m+14

Back to the equation:

-(14m+14)



We get rid of parentheses

5m-14m-14+5=0

We add all the numbers together, and all the variables

-9m-9=0

We move all terms containing m to the left, all other terms to the right

-9m=9

m=9/-9

m=-1

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