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2-2b=2-2(b-1)
We move all terms to the left:
2-2b-(2-2(b-1))=0
We calculate terms in parentheses: -(2-2(b-1)), so:We get rid of parentheses
2-2(b-1)
determiningTheFunctionDomain -2(b-1)+2
We multiply parentheses
-2b+2+2
We add all the numbers together, and all the variables
-2b+4
Back to the equation:
-(-2b+4)
-2b+2b-4+2=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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