3z+2(5-z)=-(z-2)+2

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Solution for 3z+2(5-z)=-(z-2)+2 equation: 



3z+2(5-z)=-(z-2)+2

We move all terms to the left:

3z+2(5-z)-(-(z-2)+2)=0

We add all the numbers together, and all the variables

3z+2(-1z+5)-(-(z-2)+2)=0

We multiply parentheses

3z-2z-(-(z-2)+2)+10=0



We calculate terms in parentheses: -(-(z-2)+2), so:

-(z-2)+2

We get rid of parentheses

-z+2+2

We add all the numbers together, and all the variables

-1z+4

Back to the equation:

-(-1z+4)



We add all the numbers together, and all the variables

z-(-1z+4)+10=0

We get rid of parentheses

z+1z-4+10=0

We add all the numbers together, and all the variables

2z+6=0

We move all terms containing z to the left, all other terms to the right

2z=-6

z=-6/2

z=-3

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