1/2x+42+x=180

Solution for 1/2x+42+x=180 equation:

1/2x+42+x=180

We move all terms to the left:

1/2x+42+x-(180)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We add all the numbers together, and all the variables

x+1/2x-138=0

We multiply all the terms by the denominator


x*2x-138*2x+1=0

Wy multiply elements

2x^2-276x+1=0

a = 2; b = -276; c = +1;
Δ = b2-4ac
Δ = -2762-4·2·1
Δ = 76168
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76168}=\sqrt{4*19042}=\sqrt{4}*\sqrt{19042}=2\sqrt{19042}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-276)-2\sqrt{19042}}{2*2}=\frac{276-2\sqrt{19042}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-276)+2\sqrt{19042}}{2*2}=\frac{276+2\sqrt{19042}}{4}
$