5(k+4)=35

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Solution for 5(k+4)=35 equation: 



5(k+4)=35

We move all terms to the left:

5(k+4)-(35)=0

We multiply parentheses

5k+20-35=0

We add all the numbers together, and all the variables

5k-15=0

We move all terms containing k to the left, all other terms to the right

5k=15

k=15/5

k=3

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