3(2y+10)=2(3-6y)

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Solution for 3(2y+10)=2(3-6y) equation: 



3(2y+10)=2(3-6y)

We move all terms to the left:

3(2y+10)-(2(3-6y))=0

We add all the numbers together, and all the variables

3(2y+10)-(2(-6y+3))=0

We multiply parentheses

6y-(2(-6y+3))+30=0



We calculate terms in parentheses: -(2(-6y+3)), so:

2(-6y+3)

We multiply parentheses

-12y+6

Back to the equation:

-(-12y+6)



We get rid of parentheses

6y+12y-6+30=0

We add all the numbers together, and all the variables

18y+24=0

We move all terms containing y to the left, all other terms to the right

18y=-24

y=-24/18

y=-1+1/3

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