y2+16y-36=0

Solution for y2+16y-36=0 equation:

y2+16y-36=0

We add all the numbers together, and all the variables

y^2+16y-36=0

a = 1; b = 16; c = -36;
Δ = b2-4ac
Δ = 162-4·1·(-36)
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-20}{2*1}=\frac{-36}{2}
=-18
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+20}{2*1}=\frac{4}{2}
=2
$