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z2-24z=-144
We move all terms to the left:
z2-24z-(-144)=0
We add all the numbers together, and all the variables
z^2-24z+144=0
a = 1; b = -24; c = +144;
Δ = b2-4ac
Δ = -242-4·1·144
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$z=\frac{-b}{2a}=\frac{24}{2}=12$
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