5(f+2)=2(4-f)

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Solution for 5(f+2)=2(4-f) equation: 



5(f+2)=2(4-f)

We move all terms to the left:

5(f+2)-(2(4-f))=0

We add all the numbers together, and all the variables

5(f+2)-(2(-1f+4))=0

We multiply parentheses

5f-(2(-1f+4))+10=0



We calculate terms in parentheses: -(2(-1f+4)), so:

2(-1f+4)

We multiply parentheses

-2f+8

Back to the equation:

-(-2f+8)



We get rid of parentheses

5f+2f-8+10=0

We add all the numbers together, and all the variables

7f+2=0

We move all terms containing f to the left, all other terms to the right

7f=-2

f=-2/7

f=-2/7

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