(11b+14)(7b+8)=0

Solution for (11b+14)(7b+8)=0 equation:

(11b+14)(7b+8)=0

We multiply parentheses ..

(+77b^2+88b+98b+112)=0

We get rid of parentheses

77b^2+88b+98b+112=0

We add all the numbers together, and all the variables

77b^2+186b+112=0

a = 77; b = 186; c = +112;
Δ = b2-4ac
Δ = 1862-4·77·112
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(186)-10}{2*77}=\frac{-196}{154}
=-1+3/11
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(186)+10}{2*77}=\frac{-176}{154}
=-1+1/7
$