5(a-5)=5(3a-1)

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Solution for 5(a-5)=5(3a-1) equation: 



5(a-5)=5(3a-1)

We move all terms to the left:

5(a-5)-(5(3a-1))=0

We multiply parentheses

5a-(5(3a-1))-25=0



We calculate terms in parentheses: -(5(3a-1)), so:

5(3a-1)

We multiply parentheses

15a-5

Back to the equation:

-(15a-5)



We get rid of parentheses

5a-15a+5-25=0

We add all the numbers together, and all the variables

-10a-20=0

We move all terms containing a to the left, all other terms to the right

-10a=20

a=20/-10

a=-2

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