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3/2x+11/5x=1
We move all terms to the left:
3/2x+11/5x-(1)=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 5x!=0We calculate fractions
x!=0/5
x!=0
x∈R
15x/10x^2+22x/10x^2-1=0
We multiply all the terms by the denominator
15x+22x-1*10x^2=0
We add all the numbers together, and all the variables
37x-1*10x^2=0
Wy multiply elements
-10x^2+37x=0
a = -10; b = 37; c = 0;
Δ = b2-4ac
Δ = 372-4·(-10)·0
Δ = 1369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1369}=37$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-37}{2*-10}=\frac{-74}{-20} =3+7/10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+37}{2*-10}=\frac{0}{-20} =0 $
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