k+2-2k=-2(k+6)-5(k-10)

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Solution for k+2-2k=-2(k+6)-5(k-10) equation: 



k+2-2k=-2(k+6)-5(k-10)

We move all terms to the left:

k+2-2k-(-2(k+6)-5(k-10))=0

We add all the numbers together, and all the variables

-1k-(-2(k+6)-5(k-10))+2=0



We calculate terms in parentheses: -(-2(k+6)-5(k-10)), so:

-2(k+6)-5(k-10)

We multiply parentheses

-2k-5k-12+50

We add all the numbers together, and all the variables

-7k+38

Back to the equation:

-(-7k+38)



We get rid of parentheses

-1k+7k-38+2=0

We add all the numbers together, and all the variables

6k-36=0

We move all terms containing k to the left, all other terms to the right

6k=36

k=36/6

k=6

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