5(a-1)=-2a+3(a+5)

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Solution for 5(a-1)=-2a+3(a+5) equation:



5(a-1)=-2a+3(a+5)
We move all terms to the left:
5(a-1)-(-2a+3(a+5))=0
We multiply parentheses
5a-(-2a+3(a+5))-5=0
We calculate terms in parentheses: -(-2a+3(a+5)), so:
-2a+3(a+5)
We multiply parentheses
-2a+3a+15
We add all the numbers together, and all the variables
a+15
Back to the equation:
-(a+15)
We get rid of parentheses
5a-a-15-5=0
We add all the numbers together, and all the variables
4a-20=0
We move all terms containing a to the left, all other terms to the right
4a=20
a=20/4
a=5

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