(2x+10)+(3x-10)+40=180

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Solution for (2x+10)+(3x-10)+40=180 equation: 



(2x+10)+(3x-10)+40=180

We move all terms to the left:

(2x+10)+(3x-10)+40-(180)=0

We add all the numbers together, and all the variables

(2x+10)+(3x-10)-140=0

We get rid of parentheses

2x+3x+10-10-140=0

We add all the numbers together, and all the variables

5x-140=0

We move all terms containing x to the left, all other terms to the right

5x=140

x=140/5

x=28

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