A=(3/4)b-16

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Solution for A=(3/4)b-16 equation: 



=(3/4)A-16

We move all terms to the left:

-((3/4)A-16)=0



Domain of the equation: 4)A-16)!=0

A!=0/1

A!=0

A∈R



We add all the numbers together, and all the variables

-((+3/4)A-16)=0

We multiply all the terms by the denominator


-((+3=0

We add all the numbers together, and all the variables

=0

A=0/1

A=0

Równanie nie ma rozwiązania

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